請(qǐng)問(wèn)pi工程師:
對(duì)于多路輸出的反激變壓器,測(cè)漏感時(shí)是將所有的副邊短路,還是只要短路其中的一路就可以,能不能說(shuō)說(shuō)原理是什么?
非常感謝!
多路輸出反激變壓器如何漏感,請(qǐng)pi幫忙
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@powerint_lp
應(yīng)該是把所有輸出的繞組都短接起來(lái),因?yàn)槿魏我粋€(gè)輸出繞組都可以傳遞通過(guò)原邊耦合的勵(lì)磁能量,而反激電源原邊漏感的物理意義是無(wú)法通過(guò)勵(lì)磁耦合到輸出部分的電感,所以測(cè)原邊漏感要把所有輸出繞組都短路.
非常感謝您的解答,可不可以幫我做一個(gè)題目:
To measure leakage inductance, short circuit tests are performed on the 3-winding transformer below. The results are as follows:
measure A with B shorted: 1uH
measure A with C shorted: 1uH
measure B with C shorted: 1uH
What will you measure at A if both B and C are shorted?
Give your reasons?
To measure leakage inductance, short circuit tests are performed on the 3-winding transformer below. The results are as follows:
measure A with B shorted: 1uH
measure A with C shorted: 1uH
measure B with C shorted: 1uH
What will you measure at A if both B and C are shorted?
Give your reasons?
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@power_digger
非常感謝您的解答,可不可以幫我做一個(gè)題目: Tomeasureleakageinductance,shortcircuittestsareperformedonthe3-windingtransformerbelow.Theresultsareasfollows: measureAwithBshorted:1uH measureAwithCshorted:1uH measureBwithCshorted:1uH WhatwillyoumeasureatAifbothBandCareshorted? Giveyourreasons?
圖為:
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@power_digger
圖為:
圖為
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@powerint_lp
應(yīng)該是把所有輸出的繞組都短接起來(lái),因?yàn)槿魏我粋€(gè)輸出繞組都可以傳遞通過(guò)原邊耦合的勵(lì)磁能量,而反激電源原邊漏感的物理意義是無(wú)法通過(guò)勵(lì)磁耦合到輸出部分的電感,所以測(cè)原邊漏感要把所有輸出繞組都短路.
謝謝您的解答,我這里有答案,就是看不懂:
L1+L2=1uH (1)
L1+L3=1uH (2)
L2+L3=1uH (3)
由式(1)(2)(3)得
L2=L3 (4)
L1=L2 (5)
由式(3)(4)得
L2=L3=0.5uH (6)
由式(5)(6)得
L1=L2=L3=0.5uH (7)
如果B和C短接,則
L2//L3=0.25uH
進(jìn)而A端的感值
L1+L2//L3=0.75uH
我主要想知道他為什么這算?
L1+L2=1uH (1)
L1+L3=1uH (2)
L2+L3=1uH (3)
由式(1)(2)(3)得
L2=L3 (4)
L1=L2 (5)
由式(3)(4)得
L2=L3=0.5uH (6)
由式(5)(6)得
L1=L2=L3=0.5uH (7)
如果B和C短接,則
L2//L3=0.25uH
進(jìn)而A端的感值
L1+L2//L3=0.75uH
我主要想知道他為什么這算?
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@power_digger
謝謝您的解答,我這里有答案,就是看不懂: L1+L2=1uH (1) L1+L3=1uH (2) L2+L3=1uH (3)由式(1)(2)(3)得L2=L3 (4) L1=L2 (5)由式(3)(4)得 L2=L3=0.5uH(6)由式(5)(6)得 L1=L2=L3=0.5uH(7)如果B和C短接,則L2//L3=0.25uH進(jìn)而A端的感值L1+L2//L3=0.75uH我主要想知道他為什么這算?
設(shè)1,2,3繞組漏感(單獨(dú))的分別是L1,L2,L3,繞組匝數(shù)分別是N1,N2,N3
則有:
L1+L2(N1*N1/N2/N2)=1UH
L1+L3(N1*N1/N3/N3)=1UH
L2+L3(N2*N2/N3/N3)=1UH
應(yīng)該不能簡(jiǎn)單地那么列方程計(jì)算
則有:
L1+L2(N1*N1/N2/N2)=1UH
L1+L3(N1*N1/N3/N3)=1UH
L2+L3(N2*N2/N3/N3)=1UH
應(yīng)該不能簡(jiǎn)單地那么列方程計(jì)算
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